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JEE-Main_2024
08.04.24_(S1)
Question
Consider the figure provided. 1 mol of an ideal gas is kept in a cylinder, fitted with a piston, at the position A, at $$18^{\circ}$$ C. If the piston is moved to position B, keeping the temperature unchanged, then ' x ' L atm work is done in this reversible process. x= _____ L atm. (nearest integer) [Given : Absolute temperature = $\left.{ }^{\circ} \mathrm{C}+273.15, \mathrm{R}=0.08206 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}{ }^{-1} \mathrm{~K}^{-1}\right]$
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Solution
$\begin{aligned} & \omega=-n R T \ln \left(\frac{V_2}{V_1}\right) \\ & =-1 \times .08206 \times 291.15 \ln \left(\frac{100}{10}\right) \\ & =-55.0128\end{aligned}$
Work done by system ≈55 atm lit.
Question Tags
JEE Main
Chemistry
Medium
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