The 'spin only' magnetic moment value of $\mathrm{MO}_4{ }^{2-}$ is BM. (Where M is a metal having least metallic radii. among Sc,Ti,V,Cr,Mn and Zn ).
(Given atomic number: Sc=21,Ti=22," " V=23, Cr=24,Mn=25 and Zn=30 )
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Solution
Metal having least metallic radii among Sc,Ti,V, Cr,Mn&Zn is Cr.
Spin only magnetic moment of $\mathrm{CrO}_4{ }^{2-}$.
Here $\mathrm{Cr}^{+6}$ is in $\mathrm{d}^0$ configuration (diamagnetic).
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