Xg of ethylamine is subjected to reaction with NaNO_2/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP.
X is $\_\_\_\_$ $\times 10^{-1} \mathrm{~g}$.
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Solution
given : $\mathrm{N}_2$ evolved is 2.24 Li.e. 0.1 mole.
i.e. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$ (ethyl amine) will be 4.5 g
(= 0.1 mole)
Hence the answer $=45 \times 10^{-1} \mathrm{~g}$
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