2.5 g of a non-volatile, non-electrolyte is dissolved in 100 g of water at $25^{\circ} \mathrm{C}$. The solution showed boiling point elevation by $2^{\circ} \mathrm{C}$. Assuming the solute concentration in negligible with respect to the solvent concentration, the vapour pressure of the resulting aqueous solution is $\_\_\_\_$ mm of (nearest integer)|
[Givedi Molal boiling point elevation constant of water $\left(\mathrm{K}_{\mathrm{b}}\right)=0.52 \mathrm{~K} . \mathrm{kgmol}^{-1}$,
1 atm pressure $=760 \mathrm{~mm}$ of Hg , molar mass of water $=18 \mathrm{~g} \mathrm{~mol}^{-1}$ ]