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JEE MAIN 2024
01-02-2024 S1
Question
Arrange the bonds in order of increasing ionic character in the molecules. $\mathrm{LiF}, \mathrm{K}_2 \mathrm{O}, \mathrm{N}_2, \mathrm{SO}_2$ and $\mathrm{CIF}_3$.
Select the correct option:
A
$\mathrm{CIF}_3<\mathrm{N}_2<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
B
$\mathrm{LiF}<\mathrm{K}_2 \mathrm{O}<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{N}_2$
C
$\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
D
$\mathrm{N}_2<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Increasing order of ionic character
$$ \mathrm{N}_2<\mathrm{SO}_2<\mathrm{ClF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF} $$
Ionic character depends upon difference of electronegativity (bond polarity).
Question Tags
JEE Main
Chemistry
Hard
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