A electron of hydrogen atom on an excited state is having energy $E_n$ =-0.85eV. The maximum number of allowed transitions to lower energy level is.......
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Solution
$$
\begin{aligned}
& E_n=-\frac{13.6}{n^2}=-0.85 \\
& \Rightarrow n=4
\end{aligned}
$$
No of transition
$$
=\frac{n(n-1)}{2}=\frac{4(4-1)}{2}=6
$$
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