Lowest Oxidation number of an atom in a compound $\mathrm{A}_2 \mathrm{~B}$ is -2 . The number of an electron in its valence shell is
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Solution
$A_2 B \rightarrow 2 A^{+}+B^{-2}, B^{-2}$ has complete octet in its dianionic form, thus in its atomic state it has 6 electrons in its valence shell. As it has negative charge, it has acquired two electrons to complete its octet.
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