A Particle Moving in a Circle of..... | JEE Main 2024

JEE MAIN

01-02-2024 S1

Question

A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle θ to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection θ is then given by :

Select the correct option:

$\sin ^{-1}\left[\frac{2 \mathrm{gT}^2}{\pi^2 \mathrm{R}}\right]^{\frac{1}{2}}$

$\sin ^{-1}\left[\frac{\pi^2 R}{2 \mathrm{gT}^2}\right]^{\frac{1}{2}}$

$\cos ^{-1}\left[\frac{2 \mathrm{gT}^2}{\pi^2 \mathrm{R}}\right]^{\frac{1}{2}}$

$\cos ^{-1}\left[\frac{\pi \mathrm{R}}{2 g T^2}\right]^{\frac{1}{2}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution