If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is
$\_\_\_\_$ $\times 10^{-2} \mathrm{MeV}$. (Given $1 \mathrm{u}=931 \mathrm{MeV} / \mathrm{c}^2$, atomic mass of helium $=4.002603 \mathrm{u}$ )
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