Let y=y(x) be Solution of.... | JEE Main 2024

JEE-Main 2024

06.04.24_(S1)

Question

Let $\mathrm{y}=\mathrm{y}(\mathrm{x})$ be the solution of the differential equation $\left(1+x^2\right) \frac{d y}{d x}+y=e^{\tan ^{-1} x}, \mathrm{y}(1)=0$. Then $\mathrm{y}(0)$ is $\_\_\_\_$ .

Select the correct option:

$\frac{1}{4}\left(\mathrm{e}^{\pi / 2}-1\right)$

$\frac{1}{2}\left(1-e^{\pi / 2}\right)$

$\frac{1}{4}\left(1-\mathrm{e}^{\pi / 2}\right)$

$\frac{1}{2}\left(\mathrm{e}^{\pi / 2}-1\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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