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JEE-Main 2024
06.04.24_(S1)
Question
Let $\mathrm{f}:(-\infty, \infty)-\{0\} \rightarrow \mathrm{R}$ be a differentiable function such that $f^{\prime}(1)=\lim _{a \rightarrow \infty} a^2 f\left(\frac{1}{a}\right)$. Then $\lim _{a \rightarrow \infty} \frac{a(a+1)}{2} \tan ^{-1}\left(\frac{1}{a}\right)+a^2-2 \log _e a$ is equal to $\_\_\_\_$ .
Select the correct option:
A
$\frac{3}{2}+\frac{\pi}{4}$
B
$\frac{3}{8}+\frac{\pi}{4}$
C
$\frac{5}{2}+\frac{\pi}{8}$
D
$\frac{3}{4}+\frac{\pi}{8}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Hard
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