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JEE MAIN_2023
S1_01.02.23
Question
A light of energy 12.75 eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited states. The angular momentum of the atom in the excited state is $\frac{\mathrm{x}}{\pi} \times 10^{-17} \mathrm{eVs}$ . The value of x is_______ $\left(\right.$ use $\left.\mathrm{h}=4.14 \times 10^{-15} \mathrm{eVs}, \mathrm{c}=3 \times 10^8 \mathrm{~ms}^{-1}\right)$
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Question Tags
JEE Main
Physics
Medium
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