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JEE MAINS 2023
25.01.23
Question
As shown in the figure, in an experiment to determine Young's modulus of a wire, the extension-load curve is plotted. The curve is a straight line passing through the origin and makes an angle of 45° with the load axis. The length of wire is 62.8 cm and its diameter is 4 mm. The Young's modulus is found to be x × 104 Nm–2. The value of x is _____.[
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Solution
Sol. From graphi $$ \begin{aligned} & \mathrm{F}=\Delta \mathrm{L} \\ & \mathrm{Y}=\frac{\mathrm{FL}}{\mathrm{~A} \Delta \mathrm{~L}} \\ & \mathrm{Y}=\frac{\mathrm{L}}{\mathrm{~A}} \\ & \mathrm{Y}=\frac{62.8 \times 10^{-2}}{\pi\left(2 \times 10^{-3}\right)^2} \\ & \mathrm{Y}=5 \times 10^4 \mathrm{~N} / \mathrm{m}^2 \end{aligned} $$
Question Tags
JEE Main
Physics
Medium
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