The angular momentum the electron |MODERN PHYSICSJEEMain2023

JEE MAIN 2023

10-4-2023

Question

The angular momentum for the electron in Bohr’s orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be :

Select the correct option:

$\frac{L}{2}$

zero

2 L

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Ans. (3) Sol. $$ \begin{aligned} & \mathrm{L}=\mathrm{mvr}_{\text {em }} \mathrm{r} \propto \mathrm{n}^2, \quad \mathrm{v} \propto \frac{1}{\mathrm{n}} \\ & \therefore \mathrm{~L} \propto \mathrm{n} \end{aligned} $$ Also, $\mathrm{L}=\frac{\mathrm{nh}}{2 \pi}$, Bohr orbit is, $\mathrm{L}_1=\mathrm{L}=\frac{1 \mathrm{~h}}{2 \pi}$ $$ \begin{aligned} & L_2=2[L]=2 L \\ & L_2=\frac{2 h}{2 \pi} \end{aligned} $$ So, change $=\mathrm{L}_2-\mathrm{L}_1=2 \mathrm{~L}-\mathrm{L}=\mathrm{L}$

Question Tags

JEE Main

Physics

Easy

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