The radius of $2^{\text {nd }}$ orbit of $\mathrm{He}^{+}$of Bohr's model is $\mathrm{r}_1$ and that of fourth orbit of Be ${ }^{3+}$ is represented as $\mathrm{r}_2$. Now the ratio $\frac{r_2}{r_1}$ is $x$: 1. The value of $x$ is $\_\_\_\_$
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇