Molar mass of the hydrocarbon $(X)$ which on ozonolysis consumes one mole of $O_3$ per mole of $(X)$ and gives one mole each of ethanal and propanone is $\_\_\_\_$ $\mathrm{g} \mathrm{mol}^{-1}$ (Molar mass of $\mathrm{C} \cdot 12 \mathrm{~g} \mathrm{~mol}^{-1}, \mathrm{H} \cdot 1 \mathrm{~g}$
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Hence molar mass of hydrocarbon $(X)$ is 70 .
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Hence molar mass of hydrocarbon $(X)$ is 70 .