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JEE MAIN 2023
13-4-23_S1
Question
$t_{87.5}$ is the time required for the reaction to undergo $87.5 \%$ completion and $t_{50}$ is the time required for the reaction to undergo $50 \%$ completion. The relation between $t_{87.5}$ and $t_{50}$ for a first order reaction is $t_{87.5}=$ X × t50. The value of x is ____. (Nearest integer)
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Solution
Sol. $$ \begin{aligned} & A_t=A_0 \times \frac{12.5}{100}=\frac{A_0}{8}[87.5 \% \text { complete }] \\ & A_0 \xrightarrow{t_{12}} \frac{A_0}{2} \xrightarrow{t_{12}} \frac{A_0}{4} \xrightarrow{t_{12}} \frac{A_0}{8} \\ & t_{87.5}=3 t_{1 / 2} \\ & \therefore x=3 \end{aligned} $$
Question Tags
JEE Main
Chemistry
Medium
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