Object moves at a constant speed|CIRCULAR MOTION|JEEMAIN2023

JEE MAIN_2023

S2_290123

Question

An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at x = +2m, its velocity is $-4 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}$.. The object's velocity (v) and acceleration (a) at x = –2 m will be

Select the correct option:

$\mathrm{v}=4 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}, \mathrm{a}=8 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}^2$

$\mathrm{v}=4 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}, \mathrm{a}=8 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}^2$

$\mathrm{v}=-4 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}, \mathrm{a}=8 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}^2$

$\mathrm{v}=-4 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}, \mathrm{a}=-8 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}^2$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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