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JEE MAIN 2023
31-01-23 S2
Question
If the binding energy of ground state electron in a hydrogen atom is 13.6 eV , then, the energy required to remove the electron from the second excited state of $\mathrm{Li}^{2+}$ will be: $x \times 10^{-1} e \mathrm{~V}$. The value of $x$ is $\_\_\_\_$ .
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Question Tags
JEE Main
Physics
Easy
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