The volume of HCl , containing $73 \mathrm{~g} \mathrm{~L}^{-1}$, required to completely neutralise NaOH obtained by reacting 0.69 g of metallic sodium with water, is $\_\_\_\_$ $\mathrm{mL}_{\mathrm{uc}}$ (Nearest Integer) (Given molar Masses of $\mathrm{Na}, \mathrm{Cl}, \mathrm{O}, \mathrm{H}$ are $23,35.5,16$ and $1 \mathrm{~g} \mathrm{~mol}^1$ respectively)