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JEE MAIN 2023
30-01-2023 S2
Question
In an ac generator, a rectangular coil of 100 turns each having area $14 \times 10^{-2} \mathrm{~m}^2$ is rotated at 360 rev/min about an axis perpendicular to a uniform magnetic field of magnitude 3.0 T. The maximum value of the emf produced will be _______V.
$\left(\right.$ Take $\left.\pi=\frac{22}{7}\right)$
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Solution
$\xi_{\max }=N A B \omega=100 \times 14 \times 10^{-2} \times 3 \times \frac{360 \times 2 \pi}{60}=1584 \mathrm{~V}$
Question Tags
JEE Main
Physics
Medium
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