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JEE MAIN 2023
10-04-2023 S2
Question

The electron in the $\mathrm{n}^{\text {th }}$ orbit of $\mathrm{Li}^{2+}$ is excited to ( $\mathrm{n}+1$ ) orbit using the radiation of energy $1.47 \times 10^{-17} \mathrm{~J}$ (as shown in the diagram). The value of $n$ is $\_\_\_\_$ . Given $R_H=2.18 \times 10^{-18} \mathrm{~J}$
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Question Tags
JEE Main
Chemistry
Medium
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