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JEE-Main_2024
290124_(S2)
Question
A particle is moving in a circle of radius 50 cm in such a way that at any instant the normal and tangential components of its acceleration are equal. If its speed at $t=0$ is $4 \mathrm{~m} / \mathrm{s}$, the time taken to complete the first revolution will be $\frac{1}{\alpha}\left[1-\mathrm{e}^{-2 \pi}\right]$ s, where $\alpha=\left
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Question Tags
JEE Main
Physics
Hard
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