A ball of mass dropped height |RECTILINEARMOTIONJEEMain2022

JEE MAIN 2022

26-06-2022 S1

Question

A ball of mass 0.5 kg is dropped from the height of 10m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is ............... m. $\left(\right.$ Use $\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$.

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Solution

$\begin{aligned} & v^2=u^2+2 a s \\ & 100=0+2(10) s \\ & S=5 m \\ & \text { Height from ground }=10-5=5 m\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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