The number of N atoms is 681 g of $\mathrm{C}_7 \mathrm{H}_5 \mathrm{~N}_3 \mathrm{O}_6$ is $\mathrm{x} \times 10^{21}$. The value of x is $\_\_\_\_$ $\left(\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1}\right)$ (Nearest Integer)
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