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JEE MAIN 2022
28-06-2022 S1
Question
Given below are two statements :
Statement I : $[\mathrm{Ni}(\mathrm{CN}) 4]^2$ is square planar and diamagnetic complex. with $\mathrm{dsp}^2$ hybridization for Ni but $[\mathrm{Ni}(\mathrm{CO}) 4]$ is tetrahedral. paramagnetic and with $s p^3-$hybridication for Ni.
Statement II: $\left[\mathrm{NiCl}_4\right]^{2-}$ and $[\mathrm{Ni}(\mathrm{CO}) 4]$ both have same d-electron configuration have same geometry and are paramagnetic.
In light the above statements. choose the correct answer form the options given below:
Select the correct option:
A
Both Statement I and Statement II are true.
B
Both Statement I and Statement II are false.
C
Statement I is correct but statement II is false.
D
Statement I is incorrect but statement II is true.
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$[\mathrm{Ni}(\mathrm{CN}) 4]^{2-} \sim \mathrm{d}^8$ configuration, SFL, sq. planar splitting $\left(\mathrm{dsp}^2\right)$, diamagnetic. $[\mathrm{Ni}(\mathrm{CO}) 4]$ d $\mathrm{d}^{10}$ config (after excitation), SFL, tetrahedral splitting ( $\mathrm{sp}^3$ ), diamagnetic. $\left[\mathrm{NiCl}_4\right]^{2-} \mathrm{d}^8$ config, WFL, tetrahedral splitting $\left(\mathrm{sp}^3\right)$, paramagnetic $\left(2\right.$ unpaired $\left.\mathrm{e}^{-}\right)$.
Question Tags
JEE Main
Chemistry
Easy
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