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JEE MAIN 2022
27-06-2022 S2
Question
The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be
Select the correct option:
A
$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]$
B
$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$
C
$\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
D
$\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^0\right]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Pascal second $$ \frac{F}{A} \mathrm{t}=\frac{M L T^{-2}}{L^2} T=M L^{-1} T^{-1} $$
Question Tags
JEE Main
Physics
Easy
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