The area enclosed by. | Area Under Curve

JEE MAIN 2022

29-06-22 S1

Question

The area enclosed by $y^2=8 x$ and $y=\sqrt{2} x$ that lies outside the triangle formed by $y=\sqrt{2} x, x=1, y=2 \sqrt{2}$, is equal to:

Select the correct option:

$\frac{16 \sqrt{2}}{6}$

$\frac{11 \sqrt{2}}{6}$

$\frac{13 \sqrt{2}}{6}$

$\frac{5 \sqrt{2}}{6}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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