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JEE-Main 2022
24-6-22_E1
Question
The resistance of conductivity cell containing 0.01 M KCl solution at 298 K is $1750 \Omega$. If the conductivity of 0.01 M KCl solution at 298 K is $0.152 \times 10^{-3} \mathrm{~S} \mathrm{~cm}^{-1}$, then the cell constant of the conductivity cell is $\_\_\_\_$ × $10^{-3} \mathrm{~cm}^{-1}$.
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JEE Main
Chemistry
Easy
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