Report Issue

JEE MAIN 2022
29-06-2022 S2
Question
The equation
$$ k=\left(6.5 \times 10^{12} \mathrm{~s}^{-1}\right) \mathrm{e}^{-28000 \mathrm{kJT}} $$ is followed for the decomposition of compound A .
The activation energy for the reaction is $\_\_\_\_$ $\mathrm{kJ} \mathrm{mol}{ }^{-1}$. [nearest integer]
(Given: $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ )
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \mathrm{K}=\mathrm{Ae}^{-} \mathrm{Ea} / \mathrm{RT}=\left(6.5 \times 10^{12} \mathrm{~s}^{-1}\right) \mathrm{e}^{-26000 \mathrm{KT}} \\ & \frac{\mathrm{Ea}}{8.314}=26000 \\ & \mathrm{Ea}=216.164 \mathrm{~kJ} / \mathrm{mol} .\end{aligned}$
Question Tags
JEE Main
Chemistry
Easy
Start Preparing for JEE with Competishun