$\begin{aligned} & \mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})} \\ & 20 \mathrm{~g} 5 \mathrm{~g}\end{aligned}$ Consider the above reaction, the limiting reagent of the reaction and number of moles of $\mathrm{NH}_3$ formed respectively are: