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JEE MAIN 2022
26-07-22 S1
Question
When 800 mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is $x \times 10^{-2} M$. (Nearest Integer) (Molar mass of nitric acid is $63 \mathrm{~g} \mathrm{~mol}^{-1}$ )
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JEE Main
Chemistry
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