The length of metallic wire is $\ell_1$ when tension in it is $T_1$. It is $\ell_2$ when the tension is $T_2$. The original length of the wire will be-
Select the correct option:
A
$\frac{\ell_1+\ell_2}{2}$
B
\ell_1+T_1 \ell_2}{T_1+T_2}$
C
$\frac{T_2 \ell_1+T_1 \ell_2}{T_2+T_1}$
D
$\frac{T_1 \ell_1+T_2 \ell_2}{T_2-T_1}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Assuming Hooke's law to be valid.
$$
\begin{aligned}
& \mathrm{T} \propto(\Delta \ell) \\
& \mathrm{T}=\mathrm{k}(\Delta \ell)
\end{aligned}
$$
Let $\ell_0=$ natural length (original length)
$$
\begin{aligned}
& \Rightarrow \mathrm{T}=\mathrm{K}\left(\ell-\ell_0\right) \\
& \text { so, } \mathrm{T}_1=\mathrm{k}\left(\ell_1-\ell_0\right) \& \mathrm{~T}_2=\mathrm{k}\left(\ell_2-\ell_0\right) \\
& \Rightarrow \frac{\mathrm{T}_1}{\mathrm{~T}_2}=\frac{\ell_1-\ell_0}{\ell_2-\ell_0} \\
& \Rightarrow \ell_0=\frac{\mathrm{T}_2 \ell_1-\mathrm{T}_1 \ell_2}{\mathrm{~T}_2-\mathrm{T}_1}
\end{aligned}
$$
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