A bar magnet of length 14 cm is placed | EMF

JEE MAIN 2021

16-03-2021 S1

Question

A bar magnet of length 14 cm is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of 18 cm from the center of the magnet. If $\mathrm{B}_{\mathrm{H}} =0.4 \mathrm{G}$, the magnetic moment of the magnet is $\left(1 \mathrm{G}=10^{-4} \mathrm{~T}\right)$

Select the correct option:

$2.880 \times 10^3 \mathrm{~J} \mathrm{~T}^{-1}$

$2.880 \times 10^2 \mathrm{~J} \mathrm{~T}^{-1}$

$2.880 \mathrm{~J} \mathrm{~T}^{-1}$

$28.80 \mathrm{~J} \mathrm{~T}^{-1}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution