A reversible heat engine... | Thermodynamics JEE Main 2021

JEE MAIN 2021

25-02-2021 S2

Question

A reversible heat engine converts one-fourth of the heat input into work. When the temperature of the sink is reduced by 52 K, its efficiency is doubled. The temperature in Kelvin of the source will be _________.

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Solution

$\begin{aligned} & \eta=\frac{1}{4}=1-\frac{T_2}{T_1} \\ & \frac{T_2}{T_1}=\frac{3}{4} \\ & \frac{T_2-52}{T_1}=\frac{1}{2}\end{aligned}$

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JEE Main

Physics

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