The value of the integral $\int_0^\pi|\sin 2 x| d x$ is
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Solution
$\begin{aligned} & \text { Put } 2 x=t \Rightarrow 2 d x=d t \\ & \Rightarrow I=\frac{1}{2} \int_0^{2 \pi}|\sin t| d t \\ & =\int_0^\pi|\sin t| d t \\ & =2\end{aligned}$
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