Two identical photocathodes receive|MODERN PHYSICS|JEE-MAIN

JEE MAIN 2021

17-03-2021 S2

Question

Two identical photocathodes receive the light of frequencies $f_1$ and $f_2$ respectively. If the velocities of the photo-electrons coming out are $v_1$ and $v_2$ respectively, then

Select the correct option:

$v_1^2-v_2^2=\frac{2 h}{m}\left[f_1-f_2\right]$

$v_1^2+v_2^2=\frac{2 h}{m}\left[f_1+f_2\right]$

$v_1+v_2=\left[\frac{2 h}{m}\left(f_1+f_2\right)\right]^{\frac{1}{2}}$

$v_1-v_2=\left[\frac{2 h}{m}\left(f_1-f_2\right)\right]^{\frac{1}{2}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue