In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is $\_\_\_\_$ $\%$. (Round off to the Nearest Integer). (Given atomic mass : C: $12.0 \mathrm{u}, \mathrm{H} \cdot 1.0 \mathrm{u}, \mathrm{O} ; 16.0$ u, Ni: 14.0 u )