A mass of 5 kg is | SIMPLE HARMONIC MOTION

JEE MAIN 2021

01-09-21 S2

Question

A mass of 5 kg is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length 4 m has the same period of oscillation as the spring system. What is the value of acceleration due to gravity on the planet where these experiments are performed?

Select the correct option:

$10 \mathrm{~m} / \mathrm{s}^2$ (

$5 \mathrm{~m} / \mathrm{s}^2$

$4 \mathrm{~m} / \mathrm{s}^2$

$9.8 \mathrm{~m} / \mathrm{s}^2$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

From potential energy curve $$ \begin{aligned} & U_{\max }=\frac{1}{2} k A^2 \Rightarrow 10=\frac{1}{2} k(2)^2 \\ & \Rightarrow k=5 \end{aligned} $$ Now $T_{\text {spring }}=T_{\text {pendulum }}$ $$ \begin{aligned} & 2 \pi \sqrt{\frac{5}{5}}=2 \pi \sqrt{\frac{4}{g}} \\ & \Rightarrow i=\sqrt{\frac{4}{g}} \Rightarrow g=4 \text { on planet } \end{aligned} $$

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue