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JEE MAIN 2019
08-04-2019 S2
Question
A circuit connected to an ac source of emf $e=e_0 \sin (100 t)$ with $t$ in seconds, gives a phase difference of $\frac{\pi}{4}$. between the emf e and current $i$. Which of the following circuits will exhibit this?
Select the correct option:
A
RL circuit with $\mathrm{R}=1 \mathrm{k} \Omega$ and $\mathrm{L}=10 \mathrm{mH}$
B
RL circuit with $\mathrm{R}=1 \mathrm{k} \Omega$ and $\mathrm{L}=1 \mathrm{mH}$
C
RC circuit with $\mathrm{R}=1 \mathrm{k} \Omega$ and $\mathrm{C}=10 \mu \mathrm{~F}$
D
RC circuit with $\mathrm{R}=1 \mathrm{k} \Omega$ and $\mathrm{C}=1 \mu \mathrm{~F}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
As $\phi=\frac{\pi}{4}, \mathrm{x}_{\mathrm{o}}=\mathrm{R}$
Question Tags
JEE Main
Physics
Medium
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