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JEE MAIN 2021
27-07-21 S1
Question
Consider an electrical circuit containing a two way switch ' $S$ '. Initially $S$ is open and then $T_1$ is connected to $T_2$. As the current in R = $6 \Omega$ attains a maximum value of steady state level, $T_1$ is disconnected from $T_2$ and immediately connected to $T_3$. Potential drop across $r=3 \Omega$ resistor immediately after $T_1$ is connected to $T_3$ is $\_\_\_\_$ V. (Round off to the Nearest Integer)
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Solution
When $T_1$ and $T_2$ are connected, then the steady state current in the inductor $I=\frac{6}{6}=1 \mathrm{~A}$
When $T_1$ and $T_3$ are connected then current through inductor remains same. So potential difference across $3 \Omega \mathrm{V}=\mathrm{It}=1 \times 3=3 \mathrm{volt}$
Question Tags
JEE Main
Physics
Easy
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