An electron of mass me and...|MODERN PHYSICS|JEEMAIN 2021

JEE MAIN 2021

22-07-21 S2

Question

An electron of mass me and a proton of mass $\mathrm{m}_{\mathrm{p}}$ are accelerated through the same potential difference. The ratio of the de-Broglie wavelength associated with the electron to that with the proton is :-

Select the correct option:

$\frac{\mathrm{m}_{\mathrm{p}}}{\mathrm{m}_{\mathrm{e}}}$

$\sqrt{\frac{m_p}{m_e}}$

$\frac{\mathrm{m}_{\mathrm{e}}}{\mathrm{m}_{\mathrm{p}}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

KE = eΔV λₑ = h / √(2mₑ(eΔV)) λₚ = h / √(2mₚ(eΔV)) ⇒ λₑ / λₚ = √(mₚ / mₑ)

Question Tags

JEE Main

Physics

Easy

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