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JEE-MAIN 2021
25-07-2021 S1
Question
What should be the order of arrangement of de-Broglie wavelength of electron ( $\lambda_{\mathrm{e}}$ ), an $\alpha$-particle ( $\lambda_\alpha$ ) and proton ( $\lambda_{\mathrm{p}}$ ) given that all have the same kinetic energy?
Select the correct option:
A
$\lambda_{\mathrm{e}}=\lambda_{\mathrm{p}}=\lambda_\alpha$
B
$\lambda_e<\lambda_p<\lambda_\alpha$
C
$\lambda_e>\lambda_p>\lambda_\alpha$
D
$\lambda_e=\lambda_p>\lambda_\alpha$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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