Let C be the set of all complex numbers. Let $\begin{aligned} & S_1=\left\{z \in C| | z-3-\left.2\right|^2=8\right\}, \\ & S_2=\{z \in C \mid \operatorname{Re}(z) \geq 5\} \text { and } \\ & S_3=\{z \in C| | z-\bar{z} \mid \geq 8\} .\end{aligned}$ Then the number of elements in $\mathrm{S}_1 \cap \mathrm{~S}_2 \cap \mathrm{~S}_3$ is equal to: