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JEE MAIN 2019
08-04-2019 S2
Question
Calculate the standard cell potential (in V) of the cell in which following reaction takes place : $$ \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Fe}^{3+}(\mathrm{aq})+\mathrm{Ag}(\mathrm{~s}) $$ Given that $$ \begin{aligned} & \mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^0=\mathrm{xV} \\ & \mathrm{E}_{\mathrm{Fe}^{2+/ \mathrm{Fe}}}^0=\mathrm{yV} \\ & \mathrm{E}_{\mathrm{Fe}^{3+/ \mathrm{Fe}}}^0=\mathrm{zV} \end{aligned} $$
Select the correct option:
A
x – y
B
x + y – z
C
x + 2y – 3z
D
x – z
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Chemistry
Easy
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