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JEE MAIN 2021
27-07-21 S1
Question
Let $\alpha, \beta$ be two roots of the equation $x^2+(20)^{1 / 4} x+(5)^{\frac{1}{2}}=0$. Then $\alpha^8+\beta^8$ is equal to
Select the correct option:
A
10
B
100
C
50
D
160
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Medium
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