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JEE-MAIN 2021
01-09-2021 S2
Question
The temperature of an ideal gas in 3-dimensions is 300 K. The corresponding de-Broglie wavelength of the electron approximately at 300 K is:
$\begin{aligned} & {\left[\mathrm{m}_{\mathrm{e}}=\text { mass of electron }=9 \times 10^{-31} \mathrm{~kg}\right.} \\ & \mathrm{h}=\text { Planck constant }=6.6 \times 10^{-34} \mathrm{Js} \\ & \left.\mathrm{k}_{\mathrm{B}}=\text { Boltzmann constant }=1.38 \times 10^{-23} \mathrm{JK}^{-1}\right]\end{aligned}$
Select the correct option:
A
6.26 nm
B
8.46 nm
C
2.26 nm
D
3.25 nm
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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