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JEE MAIN 2021
26.08.21_S1
Question
In a photoelectric experiment ultraviolet light of wavelength 280 nm is used with lithium cathode having work function $\phi=2.5 \mathrm{eV}$. If the wavelength of incident light is switched to 400 nm , find out the change in the stopping potential. ( $\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, \mathrm{c}=3 \times 10^8 \mathrm{~ms}^{-1}$ )
Select the correct option:
A
1.3 V
B
1.1 V
C
1.9 V
D
0.6 V
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Physics
Easy
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