Potassium chlorate is prepared by electrolysis of KCl in basic solution as shown by following equation. $ 6 \mathrm{OH}^{-}+\mathrm{Cl}^{-} \rightarrow \mathrm{ClO}_3^{-}+3 \mathrm{H}_2 \mathrm{O}+6 \mathrm{e}^{-} $ A current of $x A$ has to be passed for 10 h to produce 10.0 g of potassium chlorate the value of $x$ is $\_\_\_\_$ (Nearest integer) (Molar mass of $\mathrm{KClO}_3=122.6 \mathrm{~g} \mathrm{~mol}^{-1}, \mathrm{~F}=96500$C