Skip to content
Courses
Test Series
Books
Free Resources
Result
Contact Us
Courses
Test Series
JEE Solutions
NCERT PDF
Books
Free Resources
Gallery
Result
Blogs
Watch JEE/NEET Free Lectures
↗
Download Our App
↗
Follow Us
Login / Register
Back
Report
Report Issue
×
Wrong Answer
Typo Error
Image Issue
Not Clear
Other
JEE MAIN 2021
31-08-2021 S1
Question
If velocity [V], time [T] and force [F] are chosen as the base quantities, the dimensions of the mass will be :
Select the correct option:
A
$\left[\mathrm{FT}^{-1} \mathrm{~V}^{-1}\right]$
B
$\left[\mathrm{FTV}^{-1}\right]$
C
$\left[\mathrm{FT}^2 \mathrm{~V}\right]$
D
$\left[\mathrm{FVT}^{-1}\right]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
View Solution
Solution
$\begin{aligned} & {[\mathrm{M}]=\mathrm{K}[\mathrm{F}]^{\mathrm{a}}[\mathrm{T}]^{\mathrm{b}}[\mathrm{V}]^{\mathrm{c}}} \\ & {\left[\mathrm{M}^1\right]=\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2}\right]^{\mathrm{a}}\left[\mathrm{T}^1\right]^{\mathrm{b}}\left[\mathrm{L}^1 \mathrm{~T}^{-1}\right]^{\mathrm{c}}} \\ & \mathrm{a}=1, \mathrm{~b}=1, \mathrm{c}=-1 \\ & \therefore[\mathrm{M}]=\left[\mathrm{FTV}^{-1}\right]\end{aligned}$
Question Tags
JEE Main
Physics
Easy
Start Preparing for JEE with Competishun
YouTube
Books
App
Tests
Scan the code
Powered by
Joinchat
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation.
Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
Open Chat